Biography Digital Electronics Interview Questions And Answers Pdf


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Download here Digital Electronics Questions and Answers in PDF Check Updated Digital Electronics Interview Questions from here. DIGITAL ELECTRONICS Questions and Answers pdf free download. DIGITAL ELECTRONICS Objective type multiple choice interview. Digital Electronics Interview Questions. Check out These Most asked Digital Electronics Interview Questions and Answers and see how many can you answer .

Digital Electronics Interview Questions And Answers Pdf

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In this article, we have kept the most asked Digital Electronics Interview Questions with their answers. So that you can crack the interview with ease. Digital Electronics Interview Questions and Answers freshers can download Digital Electronics quiz questions with answers as PDF files and eBooks. + Digital Electronics Interview Questions and Answers, Question1: What is difference between latch and flip-flop? Question2: Given only two xor gates one.

What are the applications of Demultiplexer? The applications of the demultiplexer are as follows: It is used in the data transmission system with error detection. It is used as a decoder for the conversion of binary to decimal. It is used as a serial to parallel converter. What are the differences between Combinational Circuits and Sequential Circuits?

Define Rise Time? Define fall time? Define Setup time? The minimum time that is required to maintain the constant voltage levels at the excitation inputs of the flip-flop device before the triggering edge of the clock pulse for the levels to be reliably clocked in the flip flop is called the Setup time.

It is denoted as tsetup.

What is the difference between D-latch and D Flip-flop? D-latch is level sensitive whereas flip-flop is edge sensitive. Latches are faster than flip-flops. Flip- flops are made up of latches.

The main difference between latch and FF is that latches are level sensitive while FF is edge sensitive. What is a Demultiplexer? The demultiplexer is a circuit that receives the input on a single line and transmits this onto 2n possible output line. The demultiplexer is also called as Data Distributor. They both require the use of clock signal and are used in sequential logic.

The circuit that can operate on many binary inputs to perform a particular logic function is called an electronic circuit. Latch is sensitive to glitches on enable pin.

Downloaded From. Latches take fewer gates also less power to implement than flip-flops. For a latch. A Demultiplexer of 2n outputs has n select lines. What is a Logic gate? The basic gates that make up the digital system are called a logic gate.

FF on the other hand. What is meant by K-Map or Karnaugh Map? K-Map is a pictorial representation of truth table in which the map is made up of cells. Sum of products SOP form. What are the applications of Multiplexer MUX? The applications of the multiplexer are as follows: A one hot FSM design requires a flip-flop for each state in the design and only one flip-flop the flip-flop representing the current or "hot" state is set at a time in a one hot FSM design.

For a state machine with 9- 16 states, a binary FSM only requires 4 flip-flops while a one hot FSM requires a flip-flop for each state in the design FPGA vendors frequently recommend using a one hot state encoding style because flip-flops are plentiful in an FPGA and the combinational logic required to implement a one hot FSM design is typically smaller than most binary encoding styles.

Question 5. Question 6. SDRAM receives its address command in two address words. It uses a multiplex scheme to save input pins. Question 7. Question 8. Question 9. This answers why most signals are active low if you consider the transistor level of a module, active low means the capacitor in the output terminal gets charged or discharged based on low to high and high to low transition respectively. When it goes from high to low it depends on the pull down resistor that pulls it down and it is relatively easy for the output capacitance to discharge rather than charging.

Hence people prefer using active low signals. Question Basically, you can tie the inputs of a NAND gate together to get an inverter. It is well known that in left shift all bits will be shifted left and LSB will be appended with 0 and in right shift all bits will be shifted right and MSB will be appended with 0 this is a straightforward answer What is expected is in a left shift value gets Multiplied by 2 e.

D-latch is level sensitive where as flip-flop is edge sensitive. Flip-flops are made up of latches. What Is A Multiplexer? Is a combinational circuit that selects binary information from one of many input lines and directs it to a single output line. What Do They Signify? Set up time is the amount of time the data should be stable before the application of the clock signal, where as the hold time is the amount of time the data should be stable after the application of the clock.

Setup time signifies maximum delay constraints; hold time is for minimum delay constraints. Setup time is critical for establishing the maximum clock frequency.

By giving the feedback we can convert, i. Hence the S and R inputs will act as J and K respectively. By connecting the J input to the K through the inverter. XOR each bits of A with B for e. A [0] xor B [0] and so on. Convert D-ff Into Divide By 2. Freq of operation: Using 2: Give input A at the select line and 0 to I0 and B to I1. Give input A at the select line and 1 to I1 and B to I0.

It should not use any multiplier circuits. It should use Multiplexers and other logic? See a pattern yet? To get the next square, all you have to do is add the next odd number to the previous square that you found. See how 1,3,5,7 and finally 9 are added. It seems it would take n clock cycles to calculate square of n. How Does This Circuit Work? Explain In Detail?

This could also be called as odd parity generator since with this additional 1 as output the total number of 1's will be ODD. What Is Race-around Problem? How Can You Rectify It?

The clock pulse that remains in the 1 state while both J and K are equal to 1 will cause the output to complement again and repeat complementing until the pulse goes back to 0, this is called the race around problem. To avoid this undesirable operation, the clock pulse must have a time duration that is shorter than the propagation delay time of the F-F, this is restrictive so the alternative is master-slave or edge-triggered construction.

How many minimum number of 2 input NAND gates are required? All the bits of subtrahend should be connected to the xor gate.

Other input to the xor being one. The input carry bit to the full adder should be made 1. Then the full adder works like a full subtract. Setup violations are related to two edges of clock, i mean you can vary the clock frequency to correct setup violation. So, Full adder will work as a Full subtractor. A Minterm is defined as the product of Boolean expression where all possible variables will appear once in complement or un-complement variables is called Minterm.

Maxterm is defined as the sum of Boolean expression where all possible variables will appear once in complement or un-complement variables is called Maxterm. The problem of a race around condition can be solved by using an edge-triggered flip-flop. The edge-triggered flip-flop will change its state either at the positive edge or negative edge of the clock pulse. The edge-triggered flip-flop is sensitive to its inputs only at this transaction of a flip-flop.

There are two types of shift register counters such as Ring counter and Johnson counter.


Ring Counter: Ring Counter is defined as a circular shift register with only one flip-flop being set at any time and other bits will get cleared. Johnson Counter: This has been a guide to the list of Digital Electronics interview questions and Answers so that the candidate can crackdown these Digital Electronics interview questions easily.

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